Prepare the probability distribution of selecting damaged goods. The manager decided to pick 3 of the tube lights randomly. Let’s say, within 1 hour, 10 tube lights were produced, out of which 2 were damaged. One day the Operation Manager decided to randomly evaluate the effectiveness of production by evaluating the percentage of Damaged stocks produced within 1 hour. was engaged in the manufacturing of tube lights. In a similar type of situation, let’s assume a situation where a manufacturing company named ABC Inc. So, through the use of Probability distribution, the trend of employment, trend of hiring, selection of candidates, and other nature could be summarised and studied upon.
Possibility of an event where no women would be selected is & the possibility of an event where only 1 woman will be selected amounted to, whereas the possibility of selection of both women is. For the final selection, they decide to select randomly, and the number of women selected could be either 0 or 1 or 2.
So, the probability distribution for selecting women will be shown as Įxplanation: In this scenario, the management decided to fill up the 2 vacancies through interviews, and during the interview, they chose 4 people.
= Probability of selecting 1 woman + Probability of selecting 2 women. Now, as per the question, the probability of selecting at least 1 woman will be Probability of selecting 2 women =no of the possibility of selecting 2 women / total possibilities. So, the probability of selecting 1 woman = no of the possibility of selecting 1 women / total possibilities. Probability of selecting X women = no of the possibility of selecting X women / total possibilities So, the probability of selecting 0 women = no of the possibility of selecting 1 women / total possibilities. (W1, W2), (W1, M1), (W1, M2), (W2, M1), (W2, M2), (M1, M2)Īs per the requirement, let’s denote the event ‘number of women’ as X, then the possible values of X could be In the given case, the number of possibilities of selecting candidate could be, What will be the probability distribution of ‘selecting at least one woman.’ So the interviewer decided to select 2 candidates from the people present in the hall. But the concerned company had only 2 vacancies to fill. In an interview hall, there were 4 people present consisting of 2 men and 2 women after being tested by the interviewers. And the number of heads that can occur is either 0 or 1 or 2, which would be termed as possible outcomes, and the respective possibility could be 0.25, 0.5, 0.25 of the possible outcomes. So, the probability distribution for selecting heads could be shown as Įxplanation: In the given an example, the event was ‘No. Probability of selecting 2 heads =No of Possibility of Event / No of Total Possibility Probability of selecting 1 Head = No of Possibility of Event / No of Total Possibility Probability of selecting 0 Head = No of Possibility of Event / No of Total Possibility
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